Armstrong Number

Armstrong Number : Numbers who's sum of cube of digits of number is equal to same given number. Then number is called Armstrong Number .

Algorithm for Armstrong Number :

Concept of  Armstrong Number is basically Algorithm to find it . Find sum of cube of digit ,way of finding this may differ according to programming language you choose .

I use Python 2.7 So I can directly convert number into string and accessing character by character and hence find sum of cube of digits

Python Program to check Armstrong Number :

1. #ArmStrong Number
2. #http://beginer2cs.blogspot.com
4. def is_armstrong(n):
5.     temp = str(n) #convert to string
6.     summ=0
7.     for i in temp: #Find summ of cube of digits
8.         summ=summ + (int(i)**3)
10.     if summ==n:  #if sum of cube of digits == given number
11.         return True
12.     else:
13.         return False
15. if __name__=='__main__':
16.     print '''
17. Enter numbers you wanna check ,
18. they must be seperated by space
19. '''
20.     ls=[int(x) for x in raw_input().split(' ')] #taking numbers as input
21.     print "Is __ Amicable"
22.     for i in ls: #for each number print ls
23.         print str(i) +'   -->>  '+str(is_armstrong(i))

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Output :

Add caption

C- Program to check Armstrong Number :

1. //Armstrong Number in c
2. // http://beginer2cs.blogspot.com
3. #include<stdio.h>
4. int main()
5. {
6. int num,temp,sum=0,rem;
8. printf("nEnter Number to Checking Armstrong : ");
9. scanf("%d",&num);
11. temp = num;
13.  while (num != 0)
14.  {
15.   rem = num % 10;
16.   sum = sum + (rem*rem*rem);
17.   num = num / 10;
18.  }
20. if(temp == sum)
21.     printf("n%d is Amstrong Number",temp);
22. else
23.     printf("n%d is Amstrong Number",temp);
24. return(0);
25. }

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Thanks :)